(1/3)x^2-5x+25=0

Solution for (1/3)x^2-5x+25=0 equation:

(1/3)x^2-5x+25=0


Domain of the equation: 3)x^2!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+1/3)x^2-5x+25=0

We add all the numbers together, and all the variables

-5x+(+1/3)x^2+25=0

We multiply all the terms by the denominator


-5x*3)x^2+(+25*3)x^2+1=0

We add all the numbers together, and all the variables

-5x*3)x^2+75x^2+1=0

Wy multiply elements

-15x^2=0

a = -15; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-15)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-30}=0$